-43x^2+553=0

Solution for -43x^2+553=0 equation:

-43x^2+553=0

a = -43; b = 0; c = +553;
Δ = b2-4ac
Δ = 02-4·(-43)·553
Δ = 95116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{95116}=\sqrt{4*23779}=\sqrt{4}*\sqrt{23779}=2\sqrt{23779}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{23779}}{2*-43}=\frac{0-2\sqrt{23779}}{-86}
=-\frac{2\sqrt{23779}}{-86}
=-\frac{\sqrt{23779}}{-43}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{23779}}{2*-43}=\frac{0+2\sqrt{23779}}{-86}
=\frac{2\sqrt{23779}}{-86}
=\frac{\sqrt{23779}}{-43}
$